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24. The number of equal parts into which a conductor having resistance R_{0} = 100Omega should be cut to obtain the resistance R = 1Omega if the parts are connected in parallel is (C) 20 (D) 2 a (B) 10 (A) 5? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about 24. The number of equal parts into which a conductor having resistance R_{0} = 100Omega should be cut to obtain the resistance R = 1Omega if the parts are connected in parallel is (C) 20 (D) 2 a (B) 10 (A) 5? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 24. The number of equal parts into which a conductor having resistance R_{0} = 100Omega should be cut to obtain the resistance R = 1Omega if the parts are connected in parallel is (C) 20 (D) 2 a (B) 10 (A) 5?.

Solutions for 24. The number of equal parts into which a conductor having resistance R_{0} = 100Omega should be cut to obtain the resistance R = 1Omega if the parts are connected in parallel is (C) 20 (D) 2 a (B) 10 (A) 5? in English & in Hindi are available as part of our courses for UPSC. Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.

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